NCERT Solutions
Class 11 - Mathematics
Chapter 6: PERMUTATIONS AND COMBINATIONS

Complete NCERT Solutions for problems given in PERMUTATIONS AND COMBINATIONS chapter in Class 11 Mathematics.

EXERCISE 6.1

Question. 1

How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is allowed and also when repetition is not allowed?

Answer:

(i) 125

(ii) 60

Question. 2

How many 3-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?

Answer:

108

Question. 3

How many 4-letter codes can be formed using the first 10 letters of the English alphabet if no letter can be repeated?

Answer:

5040

Question. 4

How many 5-digit telephone numbers can be constructed using the digits 0 to 9 if each number starts with 67 and no digit appears more than once?

Answer:

336

Question. 5

A coin is tossed 3 times and the outcomes are recorded. How many possible outcomes are there?

Answer:

8

Question. 6

Given 5 flags of different colours, how many different signals can be generated if each signal requires the use of 2 flags, one below the other?

Answer:

20

EXERCISE 6.2

Question. 1

Evaluate:

(i) \(8!\)

(ii) \(4! - 3!\)

Answer:

(i) 40320

(ii) 18

Question. 2

Is \(3! + 4! = 7!\)?

Answer:

30, No

Question. 3

Compute \(\dfrac{8!}{6! \times 2!}\)

Answer:

28

Question. 4

If \(\dfrac{1}{6!} + \dfrac{1}{7!} = \dfrac{x}{8!}\), find \(x\)

Answer:

64

Question. 5

Evaluate \(\dfrac{n!}{(n-r)!}\) for:

(i) \(n = 6, r = 2\)

(ii) \(n = 9, r = 5\)

Answer:

(i) 30

(ii) 15120

EXERCISE 6.3

Question. 1

How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?

Answer:

504

Question. 2

How many 4-digit numbers are there with no digit repeated?

Answer:

4536

Question. 3

How many 3-digit even numbers can be made using the digits 1, 2, 3, 4, 6, 7, if no digit is repeated?

Answer:

60

Question. 4

Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. How many of these will be even?

Answer:

120, 48

Question. 5

From a committee of 8 persons, in how many ways can we choose a chairman and a vice-chairman assuming one person cannot hold more than one position?

Answer:

56

Question. 6

Find n if \( {}^{n-1}P_3 : {}^nP_4 = 1 : 9 \).

Answer:

9

Question. 7

Find r if (i) \( {}^{5}P_r = 2 \cdot {}^{6}P_{r-1} \) (ii) \( {}^{5}P_r = {}^{6}P_{r-1} \).

Answer:

(i) 3, (ii) 4

Question. 8

How many words, with or without meaning, can be formed using all the letters of the word EQUATION, using each letter exactly once?

Answer:

40320

Question. 9

How many words, with or without meaning, can be made from the letters of the word MONDAY, assuming that no letter is repeated?
(i) 4 letters are used at a time,
(ii) all letters are used at a time,
(iii) all letters are used but first letter is a vowel?

Answer:

(i) 360, (ii) 720, (iii) 240

Question. 10

In how many of the distinct permutations of the letters in MISSISSIPPI do the four I’s not come together?

Answer:

33810

Question. 11

In how many ways can the letters of the word PERMUTATIONS be arranged if the:
(i) words start with P and end with S,
(ii) vowels are all together,
(iii) there are always 4 letters between P and S?

Answer:

(i) 1814400, (ii) 2419200, (iii) 25401600

EXERCISE 6.4

Question. 1

If \( ^nC_8 = ^nC_2 \), find \( ^nC_2 \).

Answer:

\( ^nC_2 = 45 \)

Question. 2

Determine \( n \) if

(i) \( ^{2n}C_3 : ^nC_3 = 12 : 1 \)

(ii) \( ^{2n}C_3 : ^nC_3 = 11 : 1 \)

Answer:

(i) \( n = 5 \)

(ii) \( n = 6 \)

Question. 3

How many chords can be drawn through 21 points on a circle?

Answer:

\( 210 \)

Question. 4

In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and 4 girls?

Answer:

\( 40 \)

Question. 5

Find the number of ways of selecting 9 balls from 6 red balls, 5 white balls and 5 blue balls if each selection consists of 3 balls of each colour.

Answer:

\( 2000 \)

Question. 6

Determine the number of 5-card combinations out of a deck of 52 cards if there is exactly one ace in each combination.

Answer:

\( 778320 \)

Question. 7

In how many ways can one select a cricket team of eleven from 17 players in which only 5 players can bowl if each cricket team of 11 must include exactly 4 bowlers?

Answer:

\( 3960 \)

Question. 8

A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected.

Answer:

\( 200 \)

Question. 9

In how many ways can a student choose a programme of 5 courses if 9 courses are available and 2 specific courses are compulsory for every student?

Answer:

\( 35 \)

NCERT Solutions Class 11 – Mathematics – Chapter 6: PERMUTATIONS AND COMBINATIONS | Detailed Answers