Find the area of the region bounded by the ellipse \(\frac{x^2}{16} + \frac{y^2}{9} = 1\).
\(12\pi\)
Find the area of the region bounded by the ellipse \(\frac{x^2}{4} + \frac{y^2}{9} = 1\).
\(6\pi\)
Area lying in the first quadrant and bounded by the circle \(x^2 + y^2 = 4\) and the lines \(x = 0\) and \(x = 2\) is
\(\pi\)
\(\frac{\pi}{2}\)
\(\frac{\pi}{3}\)
\(\frac{\pi}{4}\)
Area of the region bounded by the curve \(y^2 = 4x\), y-axis and the line \(y = 3\) is
2
\(\frac{9}{4}\)
\(\frac{9}{3}\)
\(\frac{9}{2}\)