NCERT Exemplar Solutions
Class 11 - Mathematics - Chapter 10: STRAIGHT LINES
Match the Following

Question. 57

Match the items in Column A with Column B using the table below.

Column AColumn B

The coordinates of the points P and Q on the line \(x + 5y = 13\) which are at a distance of 2 units from the line \(12x - 5y + 26 = 0\)

(3, 1), (-7, 11)

The coordinates of the point on the line \(x + y = 4\), which are at a unit distance from the line \(4x + 3y - 10 = 0\)

\(\left(\dfrac{1}{3}, \dfrac{11}{3}\right), \left(\dfrac{4}{3}, \dfrac{7}{3}\right)\)

The coordinates of the point on the line joining A(-2,5) and B(3,1) such that AP = PQ = QB

\(\left(1, \dfrac{12}{5}\right), \left(-3, \dfrac{16}{5}\right)\)

Answer:

Column AMatched Item from Column B

The coordinates of the points P and Q on the line \(x + 5y = 13\) which are at a distance of 2 units from the line \(12x - 5y + 26 = 0\)

\(\left(1, \dfrac{12}{5}\right), \left(-3, \dfrac{16}{5}\right)\)

The coordinates of the point on the line \(x + y = 4\), which are at a unit distance from the line \(4x + 3y - 10 = 0\)

(3, 1), (-7, 11)

The coordinates of the point on the line joining A(-2,5) and B(3,1) such that AP = PQ = QB

\(\left(\dfrac{1}{3}, \dfrac{11}{3}\right), \left(\dfrac{4}{3}, \dfrac{7}{3}\right)\)

Question. 58

Match the items in Column A with Column B using the table below.

Column AColumn B

Parallel to y-axis

\(\lambda = -\dfrac{3}{4}\)

Perpendicular to \(7x + y - 4 = 0\)

\(\lambda = \dfrac{1}{3}\)

Passes through (1,2)

\(\lambda = \dfrac{17}{41}\)

Parallel to x-axis

\(\lambda = 3\)

Answer:

Column AMatched Item from Column B

Parallel to y-axis

\(\lambda = 3\)

Perpendicular to \(7x + y - 4 = 0\)

\(\lambda = -\dfrac{3}{4}\)

Passes through (1,2)

\(\lambda = \dfrac{1}{3}\)

Parallel to x-axis

\(\lambda = \dfrac{17}{41}\)

Question. 59

Match the items in Column A with Column B using the table below.

Column AColumn B

Through the point (2,1)

2x - y = 4

Perpendicular to the line \(x + 2y + 1 = 0\)

x + y - 5 = 0

Parallel to the line \(3x - 4y + 5 = 0\)

x - y - 1 = 0

Equally inclined to the axes

3x - 4y - 1 = 0

Answer:

Column AMatched Item from Column B

Through the point (2,1)

x - y - 1 = 0

Perpendicular to the line \(x + 2y + 1 = 0\)

2x - y = 4

Parallel to the line \(3x - 4y + 5 = 0\)

3x - 4y - 1 = 0

Equally inclined to the axes

x + y - 5 = 0

NCERT Exemplar Solutions Class 11 – Mathematics – Chapter 10: STRAIGHT LINES – Match the Following | Detailed Answers