NCERT Exemplar Solutions
Class 11 - Mathematics - Chapter 15: STATISTICS
Short Answer Type

Question. 1

Find the mean deviation about the mean of the distribution:

Size2021222324
Frequency64514

Answer:

0.32

Question. 2

Find the mean deviation about the median of the following distribution:

Marks obtained1011121415
No. of students23834

Answer:

1.25

Question. 3

Calculate the mean deviation about the mean of the set of first \( n \) natural numbers when \( n \) is an odd number.

Answer:

\( \dfrac{n^2 - 1}{4n} \)

Question. 4

Calculate the mean deviation about the mean of the set of first \( n \) natural numbers when \( n \) is an even number.

Answer:

\( \dfrac{n}{4} \)

Question. 5

Find the standard deviation of the first \( n \) natural numbers.

Answer:

\( \sqrt{\dfrac{n^2 - 1}{12}} \)

Question. 6

The mean and standard deviation of 25 observations are 18.2 seconds and 3.25 seconds. A second set of 15 observations has \( \sum x_i = 279 \) and \( \sum x_i^2 = 5524 \). Calculate the standard deviation of all 40 observations.

Answer:

3.87

Question. 7

The mean and standard deviation of a set of \( n_1 \) observations are \( \bar{x}_1 \) and \( s_1 \). For another set of \( n_2 \) observations, the mean and standard deviation are \( \bar{x}_2 \) and \( s_2 \). Show that the standard deviation of the combined set is:

\( \sqrt{\dfrac{n_1(s_1)^2 + n_2(s_2)^2}{n_1 + n_2} + \dfrac{n_1 n_2 (\bar{x}_1 - \bar{x}_2)^2}{(n_1 + n_2)^2}} \)

Answer:

\( \sqrt{\dfrac{n_1(s_1)^2 + n_2(s_2)^2}{n_1 + n_2} + \dfrac{n_1 n_2 (\bar{x}_1 - \bar{x}_2)^2}{(n_1 + n_2)^2}} \)

Question. 8

Two sets each of 20 observations have the same standard deviation 5. The first set has a mean 17 and the second a mean 22. Determine the standard deviation of the combined set.

Answer:

5.59

Question. 9

The frequency distribution:

xA2A3A4A5A6A
f211111

has variance 160. Determine the value of \( A \).

Answer:

7

Question. 10

For the frequency distribution:

x234567
f491614116

Find the standard deviation.

Answer:

1.38

Question. 11

The following is the frequency distribution of marks in a class of 60 students:

Marks012345
Frequencyx - 2xx^2(x + 1)^22xx + 1

Determine the mean and standard deviation where \( x \) is a positive integer.

Answer:

Mean = 2.8, SD = 1.12

Question. 12

The mean life of a sample of 60 bulbs is 650 hours with standard deviation 8 hours. A second sample of 80 bulbs has mean life 660 hours with standard deviation 7 hours. Find the overall standard deviation.

Answer:

8.9

Question. 13

A set of 100 items has mean 50 and standard deviation 4. Find the sum of all items and the sum of squares of all items.

Answer:

5000, 251600

Question. 14

For a distribution where \( \sum (x - 5) = 3 \) and \( \sum (x - 5)^2 = 43 \), and the total number of items is 18, find the mean and standard deviation.

Answer:

Mean = 5.17, SD = 1.53

Question. 15

Find the mean and variance of the following frequency distribution:

x1 ≤ x < 33 ≤ x < 55 ≤ x < 77 ≤ x < 10
f6451

Answer:

Mean = 5.5, Var = 4.26

NCERT Exemplar Solutions Class 11 – Mathematics – Chapter 15: STATISTICS – Short Answer Type | Detailed Answers