NCERT Solutions
Class 11 - Mathematics - Chapter 10: CONIC SECTIONSEXERCISE 10.2
Class 11 - Mathematics - Chapter 10: CONIC SECTIONS
Question. 1
For the parabola \(y^2 = 12x\), find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum.
Answer:
F (3, 0), axis – x-axis, directrix \(x = -3\), length of latus rectum = 12
Question. 2
For the parabola \(x^2 = 6y\), find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum.
Answer:
F \((0, \tfrac{3}{2})\), axis – y-axis, directrix \(y = -\tfrac{3}{2}\), length of latus rectum = 6
Question. 3
For the parabola \(y^2 = -8x\), find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum.
Answer:
F (−2, 0), axis – x-axis, directrix \(x = 2\), length of latus rectum = 8
Question. 4
For the parabola \(x^2 = -16y\), find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum.
Answer:
F (0, −4), axis – y-axis, directrix \(y = 4\), length of latus rectum = 16
Question. 5
For the parabola \(y^2 = 10x\), find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum.
Answer:
F \((\tfrac{5}{2}, 0)\), axis – x-axis, directrix \(x = -\tfrac{5}{2}\), length of latus rectum = 10
Question. 6
For the parabola \(x^2 = -9y\), find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum.
Answer:
F \((0, -\tfrac{9}{4})\), axis – y-axis, directrix \(y = \tfrac{9}{4}\), length of latus rectum = 9
Question. 7
Find the equation of the parabola whose focus is (6, 0) and directrix is \(x = -6\).
Answer:
\(y^2 = 24x\)
Question. 8
Find the equation of the parabola whose focus is (0, −3) and directrix is \(y = 3\).
Answer:
\(x^2 = -12y\)
Question. 9
Find the equation of the parabola with vertex (0,0) and focus (3,0).
Answer:
\(y^2 = 12x\)
Question. 10
Find the equation of the parabola with vertex (0,0) and focus (−2,0).
Answer:
\(y^2 = -8x\)
Question. 11
Find the equation of the parabola with vertex (0,0) passing through (2,3) and whose axis is along the x-axis.
Answer:
\(2y^2 = 9x\)
Question. 12
Find the equation of the parabola with vertex (0,0), passing through (5,2) and symmetric with respect to the y-axis.
Answer:
\(2x^2 = 25y\)