NCERT Solutions
Class 11 - Mathematics - Chapter 2: RELATIONS AND FUNCTIONS
EXERCISE 2.3

Question. 1

Which of the following relations are functions? Give reasons. If it is a function, determine its domain and range.

(i) {(2,1), (5,1), (8,1), (11,1), (14,1), (17,1)}

(ii) {(2,1), (4,2), (6,3), (8,4), (10,5), (12,6), (14,7)}

(iii) {(1,3), (1,5), (2,5)}

Answer:

(i) Yes, Domain = \(\{2, 5, 8, 11, 14, 17\}\), Range = \(\{1\}\)

(ii) Yes, Domain = \(\{2, 4, 6, 8, 10, 12, 14\}\), Range = \(\{1, 2, 3, 4, 5, 6, 7\}\)

(iii) No.

Question. 2

Find the domain and range of the following real functions:

(i) \(f(x) = -|x|\)

(ii) \(f(x) = \sqrt{9 - x^2}\)

Answer:

(i) Domain = \(\mathbb{R}\), Range = \(( -\infty, 0 ]\)

(ii) Domain = \(\{x : -3 \le x \le 3\}\), Range = \(\{x : 0 \le x \le 3\}\)

Question. 3

A function \(f\) is defined by \(f(x) = 2x - 5\). Write the values of:

(i) \(f(0)\)

(ii) \(f(7)\)

(iii) \(f(-3)\)

Answer:

(i) \(f(0) = -5\)

(ii) \(f(7) = 9\)

(iii) \(f(-3) = -11\)

Question. 4

The function \(t\) which maps temperature in degree Celsius into degree Fahrenheit is defined by

\[ t(C) = \dfrac{9C}{5} + 32. \]

Find:

(i) \(t(0)\)

(ii) \(t(28)\)

(iii) \(t(-10)\)

(iv) The value of \(C\) when \(t(C)=212\)

Answer:

(i) 32

(ii) \(\dfrac{412}{5}\)

(iii) 14

(iv) 100

Question. 5

Find the range of each of the following functions.

(i) \(f(x) = 2 - 3x, \ x \in \mathbb{R}, x > 0\)

(ii) \(f(x) = x^2 + 2, x\) is a real number

(iii) \(f(x) = x, x\) is a real number

Answer:

(i) Range = \(( -\infty, 2 )\)

(ii) Range = \([2, \infty)\)

(iii) Range = \(\mathbb{R}\)

NCERT Solutions Class 11 – Mathematics – Chapter 2: RELATIONS AND FUNCTIONS – EXERCISE 2.3 | Detailed Answers