NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 1: Number System - Problems and SolutionsQuestion 151
Class 6 - Mathematics - Unit 1: Number System - Problems and Solutions
Question. 151
Given below are two columns – Column I and Column II. Match each item of Column I with the corresponding item of Column II.
| Column I | Column II |
|---|---|
| (i) The difference of two consecutive whole numbers | (a) odd |
| (ii) The product of two non-zero consecutive whole numbers | (b) 0 |
| (iii) Quotient when zero is divided by another non-zero whole number | (c) 3 |
| (iv) 2 added three times, to the smallest whole number | (d) 1 |
| (v) Smallest odd prime number | (e) 6 |
| (f) even |
Answer:
(i) → (d) 1
(ii) → (f) even
(iii) → (b) 0
(iv) → (e) 6
(v) → (c) 3
Detailed Answer with Explanation:
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(i) The difference of two consecutive whole numbers → (d) 1
Consecutive means “one after another”. Example: 4 and 5.
\(5 - 4\)\(= 1\)Try any pair like 10 and 11:
\(11 - 10\)\(= 1\)The difference is always 1.
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(ii) The product of two non-zero consecutive whole numbers → (f) even
Product means multiplication. Take 3 and 4:
\(3 \times 4\)\(= 12\)One of two consecutive numbers is always even. Multiplying by an even number gives an even result. So the product is even.
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(iii) Quotient when zero is divided by another non-zero whole number → (b) 0
Dividing 0 by any non-zero number gives 0. Example:
\(0 \div 5\)\(= 0\)So the quotient is 0.
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(iv) 2 added three times, to the smallest whole number → (e) 6
The smallest whole number is 0.
\(0 + 2\)\(= 2\)\(2 + 2\)\(= 4\)\(4 + 2\)\(= 6\)So the result is 6.
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(v) Smallest odd prime number → (c) 3
Prime numbers have exactly two factors: 1 and the number itself.
2 is the smallest prime, but it is even.
The smallest odd prime is:
\(3\)Factors of 3 are only 1 and 3.
Matched Pairs
(i) → (d) 1
(ii) → (f) even
(iii) → (b) 0
(iv) → (e) 6
(v) → (c) 3