Following figures are formed by joining six unit squares. Which figure has the smallest perimeter in Fig. 6.4?

(ii)
(iii)
(iv)
(i)
A square shaped park ABCD of side 100 m has two equal rectangular flower beds each of size 10 m × 5 m (Fig. 6.5). Length of the boundary of the remaining park is

360 m
400 m
340 m
460 m
The side of a square is 10 cm. How many times will the new perimeter become if the side of the square is doubled?
2 times
4 times
6 times
8 times
Length and breadth of a rectangular sheet of paper are 20 cm and 10 cm, respectively. A rectangular piece 5 cm × 2 cm is cut from the sheet as shown in Fig. 6.6. Which statement is correct for the remaining sheet?

Perimeter remains same but area changes.
Area remains the same but perimeter changes.
Both area and perimeter are changing.
Both area and perimeter remain the same.
Two regular hexagons of perimeter 30 cm each are joined as shown in Fig. 6.7. The perimeter of the new figure is

65 cm
60 cm
55 cm
50 cm
In Fig. 6.8 which of the following is a regular polygon?

(i)
(ii)
(iii)
(iv)
7. Match the shapes (each side measures 2 cm) in Column I with the corresponding perimeters in Column II:
(A) → (iv) 28 cm
(B) → (ii) 20 cm
(C) → (v) 32 cm
(D) → (iii) 24 cm
8. Match the following:
(A) → (iii) 20
(B) → (i) 20
(C) → (ii) 18
(D) → (i) 10
Perimeter of the shaded portion in Fig. 6.9 is AB + _ + _ + _ + _ + _ + HA

Perimeter of the shaded portion in Fig. 6.9 is AB + BM + MN + NG + GH + HA
The amount of region enclosed by a plane closed figure is called its ________.
The amount of region enclosed by a plane closed figure is called its area.
Area of a rectangle with length 5 cm and breadth 3 cm is ________.
Area of a rectangle with length 5 cm and breadth 3 cm is 15 sq cm.
A rectangle and a square have the same perimeter (Fig. 6.10).
(a) The area of the rectangle is ________.
(b) The area of the square is ________.
(a) The area of the rectangle is 12 sq cm.
(b) The area of the square is 16 sq cm.
(a) 1 m = ________ cm.
(b) 1 sq cm = ________ cm × 1 cm.
(c) 1 sq m = 1 m × ________ m = 100 cm × ________ cm.
(d) 1 sq m = ________ sq cm.
(a) 1 m = 100 cm.
(b) 1 sq cm = 1 cm × 1 cm.
(c) 1 sq m = 1 m × 1 m = 100 cm × 100 cm.
(d) 1 sq m = 10000 sq cm.
If length of a rectangle is halved and breadth is doubled then the area of the rectangle obtained remains same.
Area of a square is doubled if the side of the square is doubled.
Perimeter of a regular octagon of side 6 cm is 36 cm.
A farmer who wants to fence his field, must find the perimeter of the field.
An engineer who plans to build a compound wall on all sides of a house must find the area of the compound.
To find the cost of painting a wall we need to find the perimeter of the wall.
To find the cost of a frame of a picture, we need to find the perimeter of the picture.
Four regular hexagons are drawn so as to form the design as shown in Fig. 6.11. If the perimeter of the design is 28 cm, find the length of each side of the hexagon.

Length of each side of the hexagon = 2 cm
Perimeter of an isosceles triangle is 50 cm. If one of the two equal sides is 18 cm, find the third side.
Third side of the triangle = 14 cm
Length of a rectangle is three times its breadth. Perimeter of the rectangle is 40 cm. Find its length and width.
Length = 15 cm, Breadth = 5 cm
There is a rectangular lawn 10 m long and 4 m wide in front of Meena’s house (Fig. 6.12). It is fenced along the two smaller sides and one longer side leaving a gap of 1 m for the entrance. Find the length of fencing.

Length of fencing required = 17 m
The region given in Fig. 6.13 is measured by taking one small square as a unit. What is the area of the region?

Area of the region = 18 square units
Tahir measured the distance around a square field as 200 rods (lathi). Later he found that the length of this rod was 140 cm. Find the side of this field in metres.
Side of the field = 70 m
The length of a rectangular field is twice its breadth. Jamal jogged around it four times and covered a distance of 6 km. What is the length of the field?
Length of the field = 500 m
Three squares are joined together as shown in Fig. 6.14. Their sides are 4 cm, 10 cm and 3 cm. Find the perimeter of the figure.

Perimeter of the figure = 54 cm
In Fig. 6.15 all triangles are equilateral and AB = 8 units. Other triangles have been formed by taking the mid points of the sides. What is the perimeter of the figure?

Perimeter of the figure = 48 units
Length of a rectangular field is 250 m and width is 150 m. Anuradha runs around this field 3 times. How far did she run? How many times should she run around the field to cover a distance of 4 km?
Distance covered in 3 rounds = 2.4 km; Rounds required for 4 km = 5
Bajinder runs ten times around a square track and covers 4 km. Find the length of the track.
Side of the square track = 100 m
The lawn in front of Molly’s house is 12 m × 8 m, whereas the lawn in front of Dolly’s house is 15 m × 5 m. A bamboo fencing is built around both the lawns. How much fencing is required for both?
Total fencing required = 80 m
The perimeter of a regular pentagon is 1540 cm. How long is each side?
Each side of the pentagon = 308 cm
The perimeter of a triangle is 28 cm. One of its sides is 8 cm. Write all the sides of the possible isosceles triangles with these measurements.
Sides of the triangles = (8 cm, 8 cm, 12 cm) or (10 cm, 10 cm, 8 cm)
The length of an aluminium strip is 40 cm. If the lengths in cm are measured in natural numbers, write the measurement of all the possible rectangular frames which can be made out of it.
Possible dimensions (Length × Breadth) = (19×1), (18×2), (17×3), (16×4), (15×5), (14×6), (13×7), (12×8), (11×9), (10×10)
Base of a tent is a regular hexagon of perimeter 60 cm. What is the length of each side of the base?
Length of each side = 10 cm
In an exhibition hall, there are 24 display boards each of length 1 m 50 cm and breadth 1 m. There is a 100 m long aluminium strip, which is used to frame these boards. How many boards will be framed using this strip? Find also the length of the aluminium strip required for the remaining boards.
Boards framed = 20; Additional strip required = 20 m
In the above question, how many square metres of cloth is required to cover all the display boards? What will be the length in m of the cloth used, if its breadth is 120 cm?
Cloth required = 36 m²; Length of cloth = 30 m
What is the length of outer boundary of the park shown in Fig. 6.16? What will be the total cost of fencing it at the rate of Rs 20 per metre? There is a rectangular flower bed in the center of the park. Find the cost of manuring the flower bed at the rate of Rs 50 per square metre.

Outer boundary = 1340 m; Cost of fencing = Rs 26,800; Cost of manuring = Rs 4,00,000
Total cost of fencing the park shown in Fig. 6.17 is Rs 55000. Find the cost of fencing per metre.

In Fig. 6.18 each square is of unit length.

(a) 30 units
(b) 56 sq units
(c) 10 equal parts of 5.6 sq units each
(d) No, the perimeters are not all equal.
Rectangular wall MNOP of a kitchen is covered with square tiles of 15 cm length (Fig. 6.19). Find the area of the wall.

Length of a rectangular field is 6 times its breadth. If length is 120 cm, find breadth and perimeter.
Breadth = 20 cm, Perimeter = 280 cm
Anmol has chart paper 90×40 cm, Abhishek has 50×70 cm. Which covers more area and by how much?
A rectangular path 60 m × 3 m is covered by tiles of 25 cm side. Find number of tiles.
How many square slabs of side 90 cm are needed to cover floor of area 81 sq m?
Rectangular field length 8 m, breadth 2 m. Square field has same perimeter. Find which has greater area.
Parmindar walks once around a square park and covers 800 m. Find area of park.
Side of square = 5 cm. How many times does area increase if side is doubled?
Rectangular cards 8×5 cm are cut from square chart 60 cm side. How many cards? What area left?
Magazine charges Rs 300 per 10 sq cm. Half page ad size 15×24 ÷ 2. Find cost.
Perimeter of square = 48 m. Small bed covers 18 sq m. Find area not covered, fraction, and ratio.
Not covered = 198 m²
Fraction = 18/216 = 1/12
Ratio = 1:11
Perimeter of square and rectangle same. Square side = 15 cm, rectangle one side = 18 cm. Find rectangle area.
Wire bent into small squares of side 2 cm. Total area = 28 cm². Find original length of wire.
Divide park of Fig. 6.17 into rectangles. Total area? Fertilizer per 300 sqm, how many packets?

Rectangular field area = 1600 sqm, length = 80 m. Find perimeter.
Area of each square on chess board = 4 sq cm. Find total area.
Total = 256 cm²
(a) 192 cm²
(b) 64 cm²
(a) Find all rectangles with perimeter 36 cm. (b) Find all with area 36 sq cm.
(a) Possible pairs: (1,17),(2,16),(3,15)... Areas accordingly.
(b) Possible pairs: (1,36),(2,18),(3,12)... Perimeters accordingly.
Find area and perimeter of figures in Fig. 6.20 if each square = 1 sq cm.

(i) 12 cm², 14 cm
(ii) 12 cm², 16 cm
(iii) 12 cm², 14 cm
Each square area? Whole figure area=96. Find perimeter. (Fig. 6.21)

Area each = 4 sq cm, Perimeter = 40 cm