NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 1: Number System - Problems and Solutions
Question 154

Question. 154

Write in expanded form:

(a) 74836

(b) 574021

(c) 8907010

Answer:

(a) \(70000 + 4000 + 800 + 30 + 6\)

(b) \(500000 + 70000 + 4000 + 0 + 20 + 1\)

(c) \(8000000 + 900000 + 0 + 7000 + 0 + 10\)

Detailed Answer with Explanation:

Idea: Split the number by place values (ones, tens, hundreds, thousands, ten-thousands, lakhs/millions, etc.). Each digit multiplies its place value.

(a) 74836

Digits and places:

\(7\) → ten-thousands \(= 7\times10000 = 70000\)

\(4\) → thousands \(= 4\times1000 = 4000\)

\(8\) → hundreds \(= 8\times100 = 800\)

\(3\) → tens \(= 3\times10 = 30\)

\(6\) → ones \(= 6\times1 = 6\)

Add them to get the expanded form.

(b) 574021

\(5\) → hundred-thousands \(= 5\times100000 = 500000\)

\(7\) → ten-thousands \(= 7\times10000 = 70000\)

\(4\) → thousands \(= 4\times1000 = 4000\)

\(0\) → hundreds \(= 0\times100 = 0\)

\(2\) → tens \(= 2\times10 = 20\)

\(1\) → ones \(= 1\times1 = 1\)

Write each term on a new line and add.

(c) 8907010

\(8\) → millions \(= 8\times1000000 = 8000000\)

\(9\) → hundred-thousands \(= 9\times100000 = 900000\)

\(0\) → ten-thousands \(= 0\times10000 = 0\)

\(7\) → thousands \(= 7\times1000 = 7000\)

\(0\) → hundreds \(= 0\times100 = 0\)

\(1\) → tens \(= 1\times10 = 10\)

\(0\) → ones \(= 0\times1 = 0\)

Add all the terms. Zeros show missing place values clearly.

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 1: Number System – Problems and Solutions | Detailed Answers