NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 1: Number System - Problems and Solutions
Question 192

Question. 192

Using digits 1, 2, 3 and 4 only once, determine the smallest 4-digit number divisible by 4.

Answer:

1324

Detailed Answer with Explanation:

Goal: smallest 4-digit number using 1, 2, 3, 4 once, divisible by 4.

  1. Rule: A number is divisible by 4 if its last two digits form a multiple of 4.
  2. Form all possible last-two-digit pairs from 1, 2, 3, 4.
  3. Check which pairs are multiples of 4:
    \(12\) is divisible by \(4\).
    \(24\) is divisible by \(4\).
    \(32\) is divisible by \(4\).
  4. So possible endings are:
    \(\_\_12\), \(\_\_24\), \(\_\_32\).
  5. Make the smallest thousands and hundreds digits with the remaining numbers for each ending:
    Ending \(12\): use \(3,4\) in front → \(3412\).
    Ending \(24\): use \(1,3\) in front → \(1324\).
    Ending \(32\): use \(1,4\) in front → \(1432\).
  6. Compare:
    \(1324 < 1432 < 3412\).
  7. Smallest number is \(\boxed{1324}\).
NCERT Exemplar Solutions Class 6 – Mathematics – Unit 1: Number System – Problems and Solutions | Detailed Answers