Of two natural numbers, the one having more digits is greater.
Step 1: Natural numbers do not have leading zeros. So a number like 007 is not allowed; it is just 7.
Step 2: If a number has k digits, the smallest such number is \(10^{k-1}\).
For example, for 3 digits the smallest is \(10^{3-1} = 10^2 = 100\).
Step 3: All k-digit numbers are less than \(10^k\).
For example, all 3-digit numbers are \(< 10^3 = 1000\), so the greatest 3-digit number is 999.
Step 4: Any number with k+1 digits is at least \(10^k\).
Step 5: Compare ranges:
\(\text{k-digit numbers} < 10^k\) and \(\text{(k+1)-digit numbers} \ge 10^k\).
This shows every (k+1)-digit number is bigger than every k-digit number.
Conclusion: More digits ⇒ larger number. Therefore, the statement is true.