Every multiple of a number is greater than or equal to the number.
Step 1: A multiple of a number \(n\) is any number of the form \(k \times n\), where \(k\) is a whole number \(0, 1, 2, \dots\).
Step 2: Take \(k = 0\). Then \(0 \times n = 0\). So \(0\) is a multiple of \(n\).
Step 3: If \(n > 0\), we know \(0 < n\).
Step 4: This shows there exists a multiple of \(n\) (namely \(0\)) that is less than \(n\), not \(\ge n\).
Conclusion: The statement is false.
Extra note (optional): For a negative number (e.g., \(n = -3\)), the multiple \(2 \times n = -6\) is also less than \(n\), so the statement still fails.