NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 3: Integers - Problems and SolutionsQuestion 63
Class 6 - Mathematics - Unit 3: Integers - Problems and Solutions
Question. 63
63. Temperature at 12:00 noon was \(+5^{\circ}\text{C}\). It increased by \(3^{\circ}\text{C}\) in the first hour and decreased by \(1^{\circ}\text{C}\) in the second hour. What was the temperature at 2:00 pm?
Answer:
\(+7^{\circ}\text{C}\)
Detailed Answer with Explanation:
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At 12:00 noon, temperature = (+5^circ ext{C}).
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First hour (12:00 → 1:00): it increases by (+3^circ ext{C}).
(5 + 3 = 8)
New temperature = (+8^circ ext{C}).
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Second hour (1:00 → 2:00): it decreases by (1^circ ext{C}).
(8 - 1 = 7)
Final temperature at 2:00 pm = (+7^circ ext{C}).