NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 7: Algebra - Fill in the Blanks
Question 25

Question. 25

p kg of potatoes are bought for Rs 70. Cost of 1 kg of potatoes (in Rs) is _________.

Answer:

p kg of potatoes are bought for Rs 70. Cost of 1 kg of potatoes (in Rs) is 70/p.

Detailed Answer with Explanation:

Step 1: We are told that p kilograms of potatoes cost Rs 70.

Step 2: To find the cost of 1 kilogram, use the unitary method:

Cost of 1 kg = (Total cost) ÷ (Total kilograms)

Step 3: Write the known values:

Total cost = (70) (rupees)

Total kilograms = (p) (kg)

Step 4: Substitute into the formula in small steps:

( ext{Cost of 1 kg} = dfrac{ ext{Total cost}}{ ext{Total kilograms}})

( ext{Cost of 1 kg} = dfrac{70}{p})

So, the cost of 1 kg of potatoes is (dfrac{70}{p}) rupees.

Quick check (example): If (p = 10) kg, then cost of 1 kg = (70 div 10 = 7) rupees. This matches our formula.

Note: (p) must be greater than (0); you can’t buy (0) or negative kilograms.

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 7: Algebra – Fill in the Blanks | Detailed Answers