Which of the following equations has x = 2 as a solution?
x + 2 = 5
x – 2 = 0
2x + 1 = 0
x + 3 = 6
Step-by-step check by substituting x = 2 in each option:
Option A: (x + 2 = 5)
Put (x = 2)
(2 + 2 = 4)
But the right side is (5). Since (4 eq 5), not a solution.
Option B: (x - 2 = 0)
Put (x = 2)
(2 - 2 = 0)
The right side is (0). Since (0 = 0), this is a solution.
Option C: (2x + 1 = 0)
Put (x = 2)
(2 imes 2 + 1 = 4 + 1 = 5)
The right side is (0). Since (5 eq 0), not a solution.
Option D: (x + 3 = 6)
Put (x = 2)
(2 + 3 = 5)
The right side is (6). Since (5 eq 6), not a solution.
Conclusion: Only Option B ((x - 2 = 0)) is true for (x = 2).