In a village, there are 8 water tanks to collect rain water. On a particular day, x litres of rain water is collected per tank. If 100 litres of water was already there in one of the tanks, what is the total amount of water in the tanks on that day?
8x + 100 L
What is given?
Step 1: Find the water collected from rain today in all 8 tanks.
Water per tank today = (x) litres
Number of tanks = (8)
Total water collected today = (8 imes x)
So, (8 imes x = 8x) litres
Step 2: Add the water that was already in one tank.
Already present water = (100) litres
Total water in all tanks today = (8x + 100) litres
Final Answer: (8x + 100) litres
Quick check (optional): Suppose (x = 50) litres.
Today’s collected water = (8 imes 50 = 400) litres
Total = (400 + 100 = 500) litres
This matches the formula (8x + 100) when (x = 50).