NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 7: Algebra - Problems and Solutions
Question 96

Question. 96

Sunita is half the age of her mother Geeta. Find their ages

(i) after 4 years?

(ii) before 3 years?

Answer:

(i) Sunita: x+4, Geeta: 2x+4

(ii) Sunita: x−3, Geeta: 2x−3

Detailed Answer with Explanation:

Let Sunita’s present age be (x) years.

Geeta is twice Sunita’s age, so Geeta’s present age is (2x) years.


(i) Ages after 4 years

  • Sunita’s new age = present age + 4
    (x) + (4) = (x + 4)
  • Geeta’s new age = present age + 4
    (2x) + (4) = (2x + 4)

(ii) Ages 3 years ago

  • Sunita’s past age = present age − 3
    (x)(3) = (x - 3)
  • Geeta’s past age = present age − 3
    (2x)(3) = (2x - 3)

Summary:

  • After 4 years: Sunita (x + 4), Geeta (2x + 4)
  • 3 years ago: Sunita (x - 3), Geeta (2x - 3)
NCERT Exemplar Solutions Class 6 – Mathematics – Unit 7: Algebra – Problems and Solutions | Detailed Answers