Sunita is half the age of her mother Geeta. Find their ages
(i) after 4 years?
(ii) before 3 years?
(i) Sunita: x+4, Geeta: 2x+4
(ii) Sunita: x−3, Geeta: 2x−3
Let Sunita’s present age be (x) years.
Geeta is twice Sunita’s age, so Geeta’s present age is (2x) years.
(i) Ages after 4 years
(ii) Ages 3 years ago
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