NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 7: Algebra - Problems and SolutionsQuestion 96
Class 6 - Mathematics - Unit 7: Algebra - Problems and Solutions
Question. 96
Sunita is half the age of her mother Geeta. Find their ages
(i) after 4 years?
(ii) before 3 years?
Answer:
(i) Sunita: x+4, Geeta: 2x+4
(ii) Sunita: x−3, Geeta: 2x−3
Detailed Answer with Explanation:
Let Sunita’s present age be (x) years.
Geeta is twice Sunita’s age, so Geeta’s present age is (2x) years.
(i) Ages after 4 years
- Sunita’s new age = present age + 4
(x) + (4) = (x + 4) - Geeta’s new age = present age + 4
(2x) + (4) = (2x + 4)
(ii) Ages 3 years ago
- Sunita’s past age = present age − 3
(x) − (3) = (x - 3) - Geeta’s past age = present age − 3
(2x) − (3) = (2x - 3)
Summary:
- After 4 years: Sunita (x + 4), Geeta (2x + 4)
- 3 years ago: Sunita (x - 3), Geeta (2x - 3)