Solution (Very Beginner-Friendly)
We will first draw the mirror images of the points A and B in the line l. Then we will measure the lengths and compare.
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Draw A′ (image of A in line l)
- With a set square or protractor, draw a short line from A to l that is perpendicular to l. Let it meet l at point P.
- Measure the distance AP with a ruler.
- On the other side of line l, along the same perpendicular, mark a point A′ so that the distance from P to A′ is the same as AP.
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Draw B′ (image of B in line l)
- Draw a perpendicular from B to l. Let it meet l at Q.
- Measure the distance BQ.
- On the other side of l, along the same perpendicular, mark B′ so that the distance from Q to B′ equals BQ.
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Measure the two segment lengths
- Use a ruler to measure the length AB.
- Use the ruler again to measure the length A′B′.
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Compare
( AB stackrel{?}{=} A'B' )
You will find that the two lengths are equal.
Why are they equal?
- Reflecting (taking a mirror image) in a line is a distance-preserving move. This is also called an isometry.
- Each point and its image are the same distance from the mirror line and lie on a line perpendicular to it.
( ext{dist}(A,l) = ext{dist}(A',l) )
( ext{dist}(B,l) = ext{dist}(B',l) )
- Because the whole figure is “flipped” without stretching, the distance between A and B is the same as the distance between A′ and B′.
Note: If your measured values differ slightly, it is usually due to drawing or measuring errors. Re-check the perpendiculars and equal distances from the line l.
Answer: Yes, ( AB = A'B' ).