NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 3: Integers - Problems and Solutions
Question 59

Question. 59

59. Match the items of Column I with that of Column II:

Q59 table
Column IColumn II
(i) The additive inverse of +2(A) 0
(ii) The greatest negative integer(B) −2
(iii) The greatest negative even integer(C) 2
(iv) The smallest integer greater than every negative integer(D) 1
(v) Sum of predecessor and successor of −1(E) −1

Answer:

(i) → (B) −2

(ii) → (E) −1

(iii) → (B) −2

(iv) → (A) 0

(v) → (B) −2

Detailed Answer with Explanation:

Step-by-step matching (very simple):

(i) The additive inverse of +2

Meaning: a number that makes the sum zero.

We want: (+2 + ? = 0)

So the number is: (-2)

Match: (B) (-2)

(ii) The greatest negative integer

Negative integers: (ldots, -3, -2, -1)

Greatest means “closest to zero on the right”.

So it is: (-1)

Match: (E) (-1)

(iii) The greatest negative even integer

Negative even integers: (ldots, -6, -4, -2)

Greatest here is the one nearest to zero.

So it is: (-2)

Match: (B) (-2)

(iv) The smallest integer greater than every negative integer

Every negative integer is less than (0).

The first integer greater than all negatives is (0).

Match: (A) (0)

(v) Sum of predecessor and successor of (-1)

Predecessor of (-1): (-2)

Successor of (-1): (0)

Sum: (-2 + 0)

= (-2)

Match: (B) (-2)

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 3: Integers – Problems and Solutions | Detailed Answers