NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 3: Integers - Problems and Solutions
Question 60

Question. 60

60. Compute each of the following:

Q60 list
  1. \(30 + (-25) + (-10)\)
  2. \((-20) + (-5)\)
  3. \(70 + (-20) + (-30)\)
  4. \(-50 + (-60) + 50\)
  5. \(1 + (-2) + (-3) + (-4)\)
  6. \(0 + (-5) + (-2)\)
  7. \(0 - (-6) - (+6)\)
  8. \(0 - 2 - (-2)\)

Answer:

(a) −5, (b) −25, (c) 20, (d) −60, (e) −8, (f) −7, (g) 0, (h) 0

Detailed Answer with Explanation:

p>Rules to use:

  • Adding a negative number means subtract it.
  • Subtracting a negative number means add it.
  • Zero changes nothing: (x+0=x).
  • You may add left to right in small steps.

  1. (30 + (-25) + (-10))

    (30 + (-25) = 30 - 25 = 5)

    (5 + (-10) = 5 - 10 = -5)

    Answer: (-5)

  2. ((-20) + (-5))

    Both are negative → add sizes: (20 + 5 = 25)

    Keep the negative sign → (-25)

    Answer: (-25)

  3. (70 + (-20) + (-30))

    (70 + (-20) = 70 - 20 = 50)

    (50 + (-30) = 50 - 30 = 20)

    Answer: (20)

  4. (-50 + (-60) + 50)

    First cancel opposites: (-50 + 50 = 0)

    (0 + (-60) = -60)

    Answer: (-60)

  5. (1 + (-2) + (-3) + (-4))

    (1 + (-2) = 1 - 2 = -1)

    (-1 + (-3) = -1 - 3 = -4)

    (-4 + (-4) = -4 - 4 = -8)

    Answer: (-8)

  6. (0 + (-5) + (-2))

    (0 + (-5) = -5)

    (-5 + (-2) = -5 - 2 = -7)

    Answer: (-7)

  7. (0 - (-6) - (+6))

    (0 - (-6) = 0 + 6 = 6)

    (6 - (+6) = 6 - 6 = 0)

    Answer: (0)

  8. (0 - 2 - (-2))

    (0 - 2 = -2)

    (-2 - (-2) = -2 + 2 = 0)

    Answer: (0)

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NCERT Exemplar Solutions Class 6 – Mathematics – Unit 3: Integers – Problems and Solutions | Detailed Answers