The difference between an integer and its additive inverse is always even.
Step 1: Take any integer (n).
Step 2: Its additive inverse is (-n).
Step 3: Write the difference (integer − its additive inverse):
(n - (-n))
Step 4: Subtracting a negative becomes addition:
(n - (-n) = n + n)
Step 5: Add the like terms:
(n + n = 2n)
Step 6: Any number of the form (2 imes) (integer) is even.
Therefore, (2n) is even. The statement is true.