NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Multiple Choice Questions
Question 9

Question.  9

Sum of \(\tfrac{4}{17}\) and \(\tfrac{15}{17}\) is

(A)

\(\tfrac{19}{17}\)

(B)

\(\tfrac{11}{17}\)

(C)

\(\tfrac{19}{34}\)

(D)

\(\tfrac{2}{17}\)

Detailed Answer with Explanation:

  1. Both fractions have the same denominator.
  2. Denominator = (17).
  3. Add only the numerators: (4 + 15).
  4. (4 + 15 = 19).
  5. Keep the denominator the same: (17).
  6. ( frac{4}{17} + frac{15}{17} = frac{(4+15)}{17}).
  7. ( frac{(4+15)}{17} = frac{19}{17}).

So, the sum is ( frac{19}{17}) (option A).

Note: ( frac{19}{17}) is an improper fraction. As a mixed number it is (1 frac{2}{17}).

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