NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Problems and Solutions

Question 112

Step 1: Read the energies (in J/kg).

Wheat: 3.2, Rice: 5.3, Potatoes (Cooked): 3.7, Milk: 3.0

Step 2: Find the least (smallest) number.

Compare the decimals by tenths: 3.0, 3.2, 3.7, 5.3 → the smallest is 3.0.

So, the food with the least energy is Milk (3.0 J/kg).

Step 3: Find the maximum (largest) number.

Among 3.0, 3.2, 3.7, 5.3 → the largest is 5.3.

So, the food with the maximum energy is Rice (5.3 J/kg).

Step 4: Write “least as a fraction of maximum”.

We want: least ÷ maximum.

\(\text{Fraction} = \dfrac{\text{least}}{\text{maximum}}\)

\(= \dfrac{3.0}{5.3}\)

Step 5: Remove decimals to make the fraction cleaner.

Multiply top and bottom by 10 (because each number has 1 decimal place):

\(\dfrac{3.0}{5.3} = \dfrac{3.0\times 10}{5.3\times 10}\)

\(= \dfrac{30}{53}\)

Step 6: Check if it can be simplified.

\(30 = 2\times 3\times 5\); \(53\) is a prime number.

No common factor other than 1, so the fraction is already in simplest form.

Final Answer: Least = Milk (3.0), Maximum = Rice (5.3), and

\(\displaystyle \dfrac{\text{least}}{\text{maximum}} = \dfrac{30}{53}\).