NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Problems and Solutions
Question 120

Question. 120

The fish caught by Neetu weighed \(3\tfrac{3}{4}\) kg and the fish caught by Narendra weighed \(2\tfrac{1}{2}\) kg. How much more did Neetu’s fish weigh than Narendra’s?

Answer:

\(1\tfrac{1}{4}\,\text{kg}\)

Detailed Answer with Explanation:

Goal: Find how much heavier Neetu’s fish is.

  1. Write the weights:
    Neetu: \(3\tfrac{3}{4}\,\text{kg}\)    Narendra: \(2\tfrac{1}{2}\,\text{kg}\)
  2. Change each mixed number to an improper fraction.
    \(3\tfrac{3}{4} = \dfrac{3\times 4 + 3}{4} = \dfrac{15}{4}\) kg
    \(2\tfrac{1}{2} = \dfrac{2\times 2 + 1}{2} = \dfrac{5}{2}\) kg
  3. Make the denominators the same (common denominator = 4).
    \(\dfrac{5}{2} = \dfrac{5\times 2}{2\times 2} = \dfrac{10}{4}\) kg
  4. Subtract the fractions with the same denominator:
    \(\dfrac{15}{4} - \dfrac{10}{4} = \dfrac{5}{4}\) kg
  5. Change \(\dfrac{5}{4}\) to a mixed number:
    \(\dfrac{5}{4} = 1\tfrac{1}{4}\) kg
  6. Conclusion: Neetu’s fish is \(1\tfrac{1}{4}\) kg heavier.

Quick check (optional): \(3\tfrac{3}{4}=3.75\), \(2\tfrac{1}{2}=2.5\).
\(3.75-2.5=1.25=1\tfrac{1}{4}\,\text{kg}\).

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