Goal: Find how much heavier Neetu’s fish is.
- Write the weights:
Neetu: \(3\tfrac{3}{4}\,\text{kg}\) Narendra: \(2\tfrac{1}{2}\,\text{kg}\)
- Change each mixed number to an improper fraction.
\(3\tfrac{3}{4} = \dfrac{3\times 4 + 3}{4} = \dfrac{15}{4}\) kg
\(2\tfrac{1}{2} = \dfrac{2\times 2 + 1}{2} = \dfrac{5}{2}\) kg
- Make the denominators the same (common denominator = 4).
\(\dfrac{5}{2} = \dfrac{5\times 2}{2\times 2} = \dfrac{10}{4}\) kg
- Subtract the fractions with the same denominator:
\(\dfrac{15}{4} - \dfrac{10}{4} = \dfrac{5}{4}\) kg
- Change \(\dfrac{5}{4}\) to a mixed number:
\(\dfrac{5}{4} = 1\tfrac{1}{4}\) kg
- Conclusion: Neetu’s fish is \(1\tfrac{1}{4}\) kg heavier.
Quick check (optional): \(3\tfrac{3}{4}=3.75\), \(2\tfrac{1}{2}=2.5\).
\(3.75-2.5=1.25=1\tfrac{1}{4}\,\text{kg}\).