NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Problems and Solutions
Question 129

Question. 129

Put each card in the correct bag.

Q129 cards and bags

Answer:

Bag I (Fraction less than 1): \(\dfrac{3}{7},\ \dfrac{8}{9},\ \dfrac{5}{6},\ \dfrac{6}{11},\ \dfrac{19}{25},\ \dfrac{2}{3},\ \dfrac{13}{17}\)

Bag II (Fraction equal to 1): \(\dfrac{4}{4},\ \dfrac{18}{18}\)

Bag III (Fraction greater than 1): \(\dfrac{9}{8}\)

Detailed Answer with Explanation:

Step 1: Understand the parts of a fraction.
A fraction has a numerator (top number) and a denominator (bottom number).

Step 2: Simple rule to compare with 1.
If the numerator is smaller than the denominator, the fraction is less than 1.
If they are equal, the fraction equals 1.
If the numerator is bigger than the denominator, the fraction is greater than 1.

Step 3: Check each card using the rule.

Bag I — Fractions less than 1 (numerator < denominator):

(3 < 7 Rightarrow dfrac{3}{7} < 1)
(8 < 9 Rightarrow dfrac{8}{9} < 1)
(5 < 6 Rightarrow dfrac{5}{6} < 1)
(6 < 11 Rightarrow dfrac{6}{11} < 1)
(19 < 25 Rightarrow dfrac{19}{25} < 1)
(2 < 3 Rightarrow dfrac{2}{3} < 1)
(13 < 17 Rightarrow dfrac{13}{17} < 1)

Bag II — Fractions equal to 1 (numerator = denominator):

(4 = 4 Rightarrow dfrac{4}{4} = 1)
(18 = 18 Rightarrow dfrac{18}{18} = 1)

Bag III — Fractions greater than 1 (numerator > denominator):

(9 > 8 Rightarrow dfrac{9}{8} > 1)

Final placement:
Bag I: (dfrac{3}{7}, dfrac{8}{9}, dfrac{5}{6}, dfrac{6}{11}, dfrac{19}{25}, dfrac{2}{3}, dfrac{13}{17})
Bag II: (dfrac{4}{4}, dfrac{18}{18})
Bag III: (dfrac{9}{8})

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 4: Fractions & Decimals – Problems and Solutions | Detailed Answers