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Check if 18 and 39 have a common factor bigger than 1.
Factor them:
\(18 = 2 imes 3 imes 3\)
\(39 = 3 imes 13\)
Both have a common factor \(3\).
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Divide the numerator and the denominator by \(3\):
\(dfrac{18}{39} = dfrac{18 div 3}{39 div 3} = dfrac{6}{13}\)
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Now check \(6\) and \(13\):
Factors of \(6\): \(1, 2, 3, 6\)
\(13\) is a prime number (factors: \(1, 13\)).
The only common factor is \(1\), so \(dfrac{6}{13}\) is in lowest form.
Since \(dfrac{18}{39}\) reduces to \(dfrac{6}{13}\), the original fraction was not in lowest form. Therefore, the statement is false.