NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 6: Mensuration - Problems and Solutions
Question 44

Question. 44

Anmol has chart paper 90×40 cm, Abhishek has 50×70 cm. Which covers more area and by how much?

Answer:

Anmol’s by 200 cm²

Detailed Answer with Explanation:

Step 1: Formula for area of a rectangle

Area = length × breadth.

Step 2: Area of Anmol’s chart

Length = \(90\) cm

Breadth = \(40\) cm

Area = \(90 \times 40 = 3600\ \text{cm}^2\)

Step 3: Area of Abhishek’s chart

Length = \(50\) cm

Breadth = \(70\) cm

Area = \(50 \times 70 = 3500\ \text{cm}^2\)

Step 4: Compare the areas

\(3600\ \text{cm}^2\) is greater than \(3500\ \text{cm}^2\).

Step 5: Find the difference

Difference = \(3600 - 3500 = 100\ \text{cm}^2\)

Conclusion: Anmol’s chart covers more area by \(100\ \text{cm}^2\).

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 6: Mensuration – Problems and Solutions | Detailed Answers