NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 9: Symmetry and Practical Geometry - Multiple Choice QuestionsQuestion 15
Class 6 - Mathematics - Unit 9: Symmetry and Practical Geometry - Multiple Choice Questions
Question. 15
The number of lines of symmetry in a 45°–45°–90° set-square is
0
1
2
3
Detailed Answer with Explanation:
Beginner-Friendly Explanation (Step by Step)
Shape: A 45°–45°–90° set-square is an isosceles right triangle.
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In this triangle, two angles are equal:
(45^circ) and (45^circ).
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Because the two angles are equal, the two sides opposite them are also equal:
Let the equal sides be (AB) and (AC).
So, (AB = AC).
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A line of symmetry is a line that folds the shape into two matching halves.
For an isosceles triangle, this line goes from the vertex between the equal sides to the midpoint of the base.
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Here, the vertex between the equal sides is the right-angle vertex.
Draw a line from the right-angle vertex to the midpoint of the hypotenuse.
This line is the angle bisector of (90^circ):
It splits (90^circ) into (45^circ) and (45^circ).
It is also the perpendicular bisector of the hypotenuse.
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This single line makes the two halves exactly the same.
So, there is one line of symmetry.
Answer: (1) line of symmetry. (Option B)