NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 9: Symmetry and Practical Geometry - Problems and Solutions
Question 75

Question. 75

Draw a line segment of length 7 cm. Draw its perpendicular bisector, using ruler and compasses.

Answer:

Construction: (1) Draw segment AB = 7 cm. (2) With centres A and B and radius > 3.5 cm, draw arcs above and below AB to intersect at P and Q. (3) Join PQ to get the perpendicular bisector of AB.

Detailed Answer with Explanation:

Explanation (Step by Step, in Simple Words)

Goal: We want a line that cuts AB (length 7 cm) into two equal parts and is also at a right angle (90°) to AB. This special line is called the perpendicular bisector.

Why we draw two pairs of arcs?

Points that are the same distance from both ends A and B always lie on the perpendicular bisector of AB. So, we create two points P and Q that are equally far from A and B by drawing arcs with the same radius from A and from B.

What does “same distance” mean here?

( AP = BP )

( AQ = BQ )

This happens because we used equal radii for the arcs from A and from B.

Why does line PQ bisect AB?

Since P and Q are both the same distance from A and B, they must lie on the locus of points equidistant from A and B — that locus is exactly the perpendicular bisector of AB. So joining P and Q gives that line.

Why is it perpendicular?

The perpendicular bisector is at a right angle to the segment it bisects. Therefore,

( PQ perp AB )

Why does it “bisect” (cut into two equal halves)?

Let M be the point where PQ meets AB. Because M lies on the perpendicular bisector,

( AM = MB )

Since AB is 7 cm, each half is

( AM = MB = 3.5 ext{cm} )

Quick checklist (to be sure you did it right):
  • P and Q are the intersection points of the arcs (one pair above and one pair below AB).
  • Line PQ cuts AB at M such that

    ( AM = MB )

    .
  • PQ makes a right angle with AB (90°):

    ( PQ perp AB )

    .
Small idea to remember:

Equal arcs from the two ends → intersection points are equally distant from both ends → join those points → you get the perpendicular bisector.”

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 9: Symmetry and Practical Geometry – Problems and Solutions | Detailed Answers