The mean of three numbers is 40. All the three numbers are different natural numbers. If lowest is 19, what could be highest possible number of remaining two numbers?
81
40
100
71
Mean = 40, so sum of three numbers = 120.
If lowest = 19, then sum of remaining two = 101.
For maximum highest value, take other as minimum possible natural number different from 19, i.e. 20.
So highest = 101 - 20 = 81.