12. In Fig. 9.19, EFGH is a parallelogram, altitudes FK and FI are 8 cm and 4 cm respectively. If EF = 10 cm, then area of EFGH is
(a) 20 cm²
(b) 32 cm²
(c) 40 cm²
(d) 80 cm²
Area of parallelogram = base × height.
Using EF = 10 cm and FK = 4 cm (altitude on EF).
So area = 10 × 4 = 40 cm².