9. Area of triangle MNO of Fig. 9.17 is
(a) \( \tfrac{1}{2} MN \times NO \)
(b) \( \tfrac{1}{2} NO \times MO \)
(c) \( \tfrac{1}{2} MN \times OQ \)
(d) \( \tfrac{1}{2} NO \times OQ \)
In \( \triangle MNO \), the base is NO and the corresponding altitude is OQ.
So, area = \( \tfrac{1}{2} \times NO \times OQ \).