NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Fill in the Blanks (Relation)Question 67
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Fill in the Blanks (Relation)
Question. 67
\(\tfrac{8}{15} \, ... \, \tfrac{95}{14}\)
Answer:
\(\tfrac{8}{15} \, < \, \tfrac{95}{14}\)
Detailed Answer with Explanation:
We want to compare \(\tfrac{8}{15}\) and \(\tfrac{95}{14}\).
Both are positive fractions. We can compare them using cross-multiplication.
- Multiply the first numerator by the second denominator:
\(8 \times 14 = 112\). - Multiply the second numerator by the first denominator:
\(95 \times 15 = 1425\). - Compare the two products:
\(112 < 1425\).
When \(a, b, c, d > 0\), if \(a \times d < c \times b\), then \(\tfrac{a}{b} < \tfrac{c}{d}\).
So, \(\tfrac{8}{15} < \tfrac{95}{14}\).
(Quick check with decimals, optional)
\(8 \div 15 \approx 0.53\) and \(95 \div 14 \approx 6.79\).
Since \(0.53 < 6.79\), the result is the same.