NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Problems and Solutions
Question 114

Question. 114

Mary bought \(3\dfrac{1}{2}\) m of lace. She used \(1\dfrac{3}{4}\) m. How much lace is left?

Answer:

\(1\dfrac{3}{4}\,\text{m}\)

Detailed Answer with Explanation:

We need to find: total lace − used lace.

Write the mixed numbers as improper fractions.

\(3\dfrac{1}{2}\): \(3\times 2 = 6\), then \(6+1=7\).

So, \(3\dfrac{1}{2} = \dfrac{7}{2}\).

\(1\dfrac{3}{4}\): \(1\times 4 = 4\), then \(4+3=7\).

So, \(1\dfrac{3}{4} = \dfrac{7}{4}\).

Make denominators the same (LCM of 2 and 4 is 4).

\(\dfrac{7}{2} = \dfrac{14}{4}\).

Now subtract the fractions.

\(\dfrac{14}{4} - \dfrac{7}{4} = \dfrac{7}{4}\).

Change \(\dfrac{7}{4}\) back to a mixed number.

\(\dfrac{7}{4} = 1\dfrac{3}{4}\).

Lace left = \(1\dfrac{3}{4}\,\text{m}\).

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 4: Fractions & Decimals – Problems and Solutions | Detailed Answers