Sunita found on Monday that she had gained \(1\dfrac{1}{4}\,\text{kg}\). Earlier her weight was \(46\dfrac{3}{8}\,\text{kg}\). What was her weight on Monday?
\(47\dfrac{5}{8}\,\text{kg}\)
Goal: Sunita gained weight on Monday. So, we add the gain to the earlier weight.
Given:
Earlier weight = \(46\dfrac{3}{8}\,\text{kg}\)
Gain = \(1\dfrac{1}{4}\,\text{kg}\)
Step 1: Use the same kind of fractions.
We already have eighths (\(\dfrac{\;}{8}\)) in \(46\dfrac{3}{8}\).
Change \(\dfrac{1}{4}\) into eighths: \(\dfrac{1}{4}=\dfrac{2}{8}\).
So, \(1\dfrac{1}{4}=1+\dfrac{2}{8}\).
Step 2: Add whole parts and fraction parts separately.
Whole parts: \(46+1=47\).
Fraction parts: \(\dfrac{3}{8}+\dfrac{2}{8}=\dfrac{5}{8}\).
Step 3: Combine the whole and fraction parts.
\(47\) and \(\dfrac{5}{8}\) together give \(47\dfrac{5}{8}\,\text{kg}\).
Answer: \(\boxed{47\dfrac{5}{8}\,\text{kg}}\).
(Quick check in decimals: \(46\dfrac{3}{8}=46.375\), \(1\dfrac{1}{4}=1.25\). Add: \(46.375+1.25=47.625=47\dfrac{5}{8}\).)