NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Problems and Solutions
Question 126

Question. 126

For the collection \(-3,-2,-1,0,1,2,3\), write the fraction representing total natural numbers; what will it be for whole numbers and for integers?

Answer:

Natural numbers: \(\dfrac{3}{7}\); Whole numbers: \(\dfrac{4}{7}\); Integers: \(\dfrac{7}{7}=1\)

Detailed Answer with Explanation:

Given collection: −3, −2, −1, 0, 1, 2, 3

Total number of items:

(7)


Natural numbers (start from 1):

In the list: ( {1, 2, 3} )

Count: (3)

Fraction = ( dfrac{ ext{natural numbers}}{ ext{total}} )

( dfrac{3}{7} )


Whole numbers (start from 0):

In the list: ( {0, 1, 2, 3} )

Count: (4)

Fraction = ( dfrac{4}{7} )


Integers (…, −2, −1, 0, 1, 2, …):

The entire list contains only integers.

Count: (7)

Fraction = ( dfrac{7}{7} )

( dfrac{7}{7} = 1 )


Final answers:

Natural numbers: ( dfrac{3}{7} )

Whole numbers: ( dfrac{4}{7} )

Integers: ( dfrac{7}{7} = 1 )

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 4: Fractions & Decimals – Problems and Solutions | Detailed Answers