NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Problems and Solutions
Question 127

Question. 127

Write a pair of fractions whose sum is \(\dfrac{7}{11}\) and difference is \(\dfrac{2}{11}\).

Answer:

\(\dfrac{9}{22}\) and \(\dfrac{5}{22}\)

Detailed Answer with Explanation:

Let the two fractions be \(a\) and \(b\).

Given:

\(a + b = \dfrac{7}{11}\)

\(a - b = \dfrac{2}{11}\)

Step 1: Find \(a\) by adding the two equations.

\((a + b) + (a - b) = \dfrac{7}{11} + \dfrac{2}{11}\)

Left side simplifies to \(2a\).

Right side is \(\dfrac{9}{11}\).

So, \(2a = \dfrac{9}{11}\).

Divide both sides by \(2\): \(a = \dfrac{9}{11} \times \dfrac{1}{2} = \dfrac{9}{22}\).

Step 2: Find \(b\) by subtracting the second equation from the first.

\((a + b) - (a - b) = \dfrac{7}{11} - \dfrac{2}{11}\)

Left side simplifies to \(2b\).

Right side is \(\dfrac{5}{11}\).

So, \(2b = \dfrac{5}{11}\).

Divide both sides by \(2\): \(b = \dfrac{5}{11} \times \dfrac{1}{2} = \dfrac{5}{22}\).

Answer: The fractions are \(\dfrac{9}{22}\) and \(\dfrac{5}{22}\).

Quick Check:

Sum: \(\dfrac{9}{22} + \dfrac{5}{22} = \dfrac{14}{22} = \dfrac{7}{11}\)

Difference: \(\dfrac{9}{22} - \dfrac{5}{22} = \dfrac{4}{22} = \dfrac{2}{11}\)

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 4: Fractions & Decimals – Problems and Solutions | Detailed Answers