NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Problems and Solutions
Question 96

Question. 96

Add the fractions \(\dfrac{3}{8}\) and \(6\dfrac{3}{4}\).

Answer:

\(7\dfrac{1}{8}\)

Detailed Answer with Explanation:

  1. Write the problem clearly: add \(6\dfrac{3}{4}\) and \(\dfrac{3}{8}\).
  2. Keep the whole number part separate for now: we have \(6\) and the fractions \(\dfrac{3}{4}\) and \(\dfrac{3}{8}\).
  3. Make the denominators the same. The common denominator of \(4\) and \(8\) is \(8\).
  4. Change \(\dfrac{3}{4}\) to eighths:
    \(\dfrac{3}{4} = \dfrac{3\times 2}{4\times 2} = \dfrac{6}{8}\).
  5. Now add the fractions:
    \(\dfrac{6}{8} + \dfrac{3}{8} = \dfrac{9}{8}\).
  6. \(\dfrac{9}{8}\) is an improper fraction. Write it as a mixed number:
    \(\dfrac{9}{8} = 1\dfrac{1}{8}\).
  7. Add this to the whole number \(6\):
    \(6 + 1\dfrac{1}{8} = 7\dfrac{1}{8}\).
  8. Answer: \(7\dfrac{1}{8}\).
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