NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - Problems and Solutions
Question 96

Question. 96

Add the fractions \(\dfrac{3}{8}\) and \(6\dfrac{3}{4}\).

\(7\dfrac{1}{8}\)

Write the problem clearly: add \(6\dfrac{3}{4}\) and \(\dfrac{3}{8}\).
Keep the whole number part separate for now: we have \(6\) and the fractions \(\dfrac{3}{4}\) and \(\dfrac{3}{8}\).
Make the denominators the same. The common denominator of \(4\) and \(8\) is \(8\).
Change \(\dfrac{3}{4}\) to eighths:
\(\dfrac{3}{4} = \dfrac{3\times 2}{4\times 2} = \dfrac{6}{8}\).
Now add the fractions:
\(\dfrac{6}{8} + \dfrac{3}{8} = \dfrac{9}{8}\).
\(\dfrac{9}{8}\) is an improper fraction. Write it as a mixed number:
\(\dfrac{9}{8} = 1\dfrac{1}{8}\).
Add this to the whole number \(6\):
\(6 + 1\dfrac{1}{8} = 7\dfrac{1}{8}\).
Answer: \(7\dfrac{1}{8}\).