Subtract \(\dfrac{1}{6}\) from \(\dfrac{1}{2}\).
\(\dfrac{1}{3}\)
We want to find: \(\dfrac{1}{2} - \dfrac{1}{6}\).
Make the denominators the same.
The smallest number that both 2 and 6 divide into is 6 (this is the LCM).
Change \(\dfrac{1}{2}\) to sixths.
Multiply top and bottom by 3:
\[ \dfrac{1}{2} \times \dfrac{3}{3} = \dfrac{3}{6} \]
Now subtract the fractions.
Keep the denominator 6 and subtract the numerators:
\[ \dfrac{3}{6} - \dfrac{1}{6} = \dfrac{2}{6} \]
Simplify the answer.
Divide top and bottom by 2:
\[ \dfrac{2}{6} = \dfrac{1}{3} \]
Final Answer: \(\dfrac{1}{3}\).