Subtract \(8\dfrac{1}{3}\) from \(\dfrac{100}{9}\).
\(\dfrac{25}{9}=2\dfrac{7}{9}\)
We want to do: \(\dfrac{100}{9} - 8\dfrac{1}{3}\).
Change the mixed number to an improper fraction.
Multiply the whole number by the denominator and add the numerator:
\[8\times 3 + 1 = 24 + 1 = 25\]
So, \(8\dfrac{1}{3} = \dfrac{25}{3}\).
Make the denominators the same (9).
Convert \(\dfrac{25}{3}\) to ninths:
\[\dfrac{25}{3} = \dfrac{25\times 3}{3\times 3} = \dfrac{75}{9}\]
Subtract the fractions.
Now both have denominator 9:
\[\dfrac{100}{9} - \dfrac{75}{9} = \dfrac{100 - 75}{9} = \dfrac{25}{9}\]
Write as a mixed number (optional).
\(25\div 9 = 2\) with remainder \(7\):
\[\dfrac{25}{9} = 2\dfrac{7}{9}\]
Final answer: \(\dfrac{25}{9}\) or \(2\dfrac{7}{9}\).