NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - True or False Questions
Question 61

Question. 61

3.03+0.016=3.019

Answer:

true

Detailed Answer with Explanation:

Idea: Add the decimals by lining up the place values.

Step 1: Write with the same number of decimal places.
\(3.03 = 3.030\)
\(0.016 = 0.016\)

Step 2: Add from the right (thousandths place).
Thousandths: \(0 + 6 = 6\) → write \(6\) in the thousandths place.

Step 3: Hundredths place.
Hundredths: \(3 + 1 = 4\) → write \(4\) in the hundredths place.

Step 4: Tenths place.
Tenths: \(0 + 0 = 0\) → write \(0\) in the tenths place.

Step 5: Ones place (whole numbers).
Ones: \(3 + 0 = 3\) → write \(3\) in the ones place.

Step 6: Write the final sum.
\(3.030 + 0.016 = 3.046\)

Conclusion: The statement says \(3.03 + 0.016 = 3.019\), but the correct sum is \(3.046\).
So the statement is false.

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 4: Fractions & Decimals – True or False Questions | Detailed Answers