NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 4: Fractions & Decimals - True or False Questions

Question 62

Goal: Subtract 3.19 from 42.28.

1. Line up decimals (same place under same place).

   We will subtract place by place.

2. Hundredths place (the second digit after the decimal):

   We need to do \(8 - 9\). We cannot do that directly.

   Borrow \(1\) tenth from the tenths place.

   Now the tenths digit \(2\) becomes \(1\).

   The hundredths digit becomes \(8 + 10 = 18\).

   Now subtract: \(18 - 9 = 9\).

3. Tenths place (the first digit after the decimal):

   After borrowing, we have \(1 - 1 = 0\).

4. Put the decimal point straight down in the answer.

5. Ones place (to the left of the decimal):

   We need to do \(2 - 3\). We cannot do that directly.

   Borrow \(1\) ten from the tens place.

   The tens digit \(4\) becomes \(3\).

   The ones digit becomes \(2 + 10 = 12\).

   Now subtract: \(12 - 3 = 9\).

6. Tens place (the second digit to the left):

   Now do \(3 - 0 = 3\).

7. Combine the digits: tens \(3\), ones \(9\), decimal point, tenths \(0\), hundredths \(9\).

   Answer: \(39.09\).

8. Quick check (optional): Add back to see if we get the original number.

   \(39.09 + 3.19 = 42.28\) ✔️