NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 9: Symmetry and Practical Geometry - Problems and Solutions
Question 67

Question. 67

Match the following:

ShapeNumber of lines of symmetry
(i) Isosceles triangle(a) 6
(ii) Square(b) 5
(iii) Kite(c) 4
(iv) Equilateral triangle(d) 3
(v) Rectangle(e) 2
(vi) Regular hexagon(f) 1
(vii) Scalene triangle(g) 0

Answer:

(i)→(f), (ii)→(c), (iii)→(f), (iv)→(d), (v)→(e), (vi)→(a), (vii)→(g)

Detailed Answer with Explanation:

Explanation (Step by Step)

What is a line of symmetry? It is a line that divides a shape into two equal mirror parts. If you fold the shape along this line, both sides match exactly.

  1. Isosceles triangle — two equal sides and equal base angles. It has one vertical line that splits it into two same halves.

    ( ext{Lines of symmetry} = 1)

  2. Square — all sides equal and all angles right angles. It has 4 symmetry lines: 2 through midpoints (horizontal & vertical) and 2 diagonals.

    ( ext{Lines of symmetry} = 4)

  3. Kite — two pairs of equal adjacent sides. Only the line through the longer diagonal (joining the unequal angles) is a symmetry line.

    ( ext{Lines of symmetry} = 1)

  4. Equilateral triangle — all sides and angles equal. Each vertex to the midpoint of the opposite side gives a symmetry line (3 in total).

    ( ext{Lines of symmetry} = 3)

  5. Rectangle — opposite sides equal, all angles right angles. It has 2 symmetry lines through the midpoints: one horizontal and one vertical (diagonals are not symmetry lines unless it’s a square).

    ( ext{Lines of symmetry} = 2)

  6. Regular hexagon — all sides and angles equal. Every vertex-to-opposite-vertex and midpoint-to-opposite-midpoint is a symmetry line (total 6).

    ( ext{Lines of symmetry} = 6)

  7. Scalene triangle — all sides different. No fold makes two equal halves.

    ( ext{Lines of symmetry} = 0)

Now match each shape to its symmetry count

Shape Number of Lines of Symmetry Match
(i) Isosceles triangle (f) 1 (i) → (f)
(ii) Square (c) 4 (ii) → (c)
(iii) Kite (f) 1 (iii) → (f)
(iv) Equilateral triangle (d) 3 (iv) → (d)
(v) Rectangle (e) 2 (v) → (e)
(vi) Regular hexagon (a) 6 (vi) → (a)
(vii) Scalene triangle (g) 0 (vii) → (g)

Final Answer: (i)→(f), (ii)→(c), (iii)→(f), (iv)→(d), (v)→(e), (vi)→(a), (vii)→(g)

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 9: Symmetry and Practical Geometry – Problems and Solutions | Detailed Answers