NCERT Exemplar Solutions
Class 7 - Mathematics - Unit 1: Number System

Fill in the Blanks

(–a) + b = b + Additive inverse of ________.

______ ÷ (–10) = 0

(–157) × (–19) + 157 = ________

[(–8) + ______ ] + ______ = ______ + [(–3) + ______ ] = –3

On the following number line, (–4) × 3 is represented by the point ________.

If x, y and z are integers then (x+ ___ ) + z = ___ + (y + ___ )

(–43) + _____ = –43

(–8) + (–8) + (–8) = _____ × (–8)

11 × (–5) = – ( ____ × ____ ) = ____

(–9) × 20 = ____

(–23) × (42) = (–42) × ____

While multiplying a positive integer and a negative integer, we multiply them as ______ numbers and put a ______ sign before the product.

If we multiply ______ number of negative integers, then the resulting integer is positive.

If we multiply six negative integers and six positive integers, then the resulting integer is ______.

If we multiply five positive integers and one negative integer, then the resulting integer is ______.

______ is the multiplicative identity for integers.

We get additive inverse of an integer a when we multiply it by ______.

(–25) × (–2) = ______

(–5) × (–6) × (–7) = ______

3 × (–1) × (–15) = ______

[12 × (–7)] × 5 = ______ × [(–7) × ______ ]

23 × (–99) = ______ × (–100 + ______ ) = 23 × ______ + 23 × ______

______ × (–1) = –35

______ × (–1) = 47