For a non-zero integer \(a\) which of the following is not defined?
\(a\div 0\)
\(0\div a\)
\(a\div 1\)
\(1\div a\)
Why is the answer (a) (a div 0)?
Key idea of division: Saying “(a div b = x)” means “(b imes x = a)”. We’ll check each option using this idea.
(a div 0) (with (a eq 0))
(a div 0 = x ;;Longleftrightarrow;; 0 imes x = a)
But for any number (x),
(0 imes x = 0)
We need it to be (a) (and (a eq 0)). This is impossible. So division by zero is not defined.
(0 div a) (with (a eq 0))
(0 div a = x ;;Longleftrightarrow;; a imes x = 0)
This is true when
(x = 0)
So (0 div a) is defined and equals 0.
(a div 1)
(a div 1 = x ;;Longleftrightarrow;; 1 imes x = a)
That gives
(x = a)
So (a div 1 = a). It’s defined.
(1 div a) (with (a eq 0))
(1 div a = x ;;Longleftrightarrow;; a imes x = 1)
That gives
(x = rac{1}{a})
So (1 div a) is defined and equals ( frac{1}{a}).
Conclusion: Only (a div 0) is not defined. Hence, option (a).