The lowest form of the product \(2\dfrac{3}{7}\times\dfrac{7}{9}\) is ______
The lowest form of the product \(2\dfrac{3}{7}\times\dfrac{7}{9}\) is \(\dfrac{17}{9}\).
\(2\dfrac{3}{7}=\dfrac{17}{7}\). So product \(=\dfrac{17}{7}\times\dfrac{7}{9}=\dfrac{17}{9}=1\dfrac{8}{9}\).