\(\dfrac{2}{5} \times 5\dfrac{1}{5}\) is equal to:
\(\dfrac{26}{25}\)
\(\dfrac{52}{25}\)
\(\dfrac{2}{5}\)
\(6\)
\(3\dfrac{3}{4} \div \dfrac{3}{4}\) is equal to:
\(3\)
\(4\)
\(5\)
\(\dfrac{45}{16}\)
A ribbon of length \(5\dfrac{1}{4}\) m is cut into small pieces each of length \(\dfrac{3}{4}\) m. Number of pieces will be:
5
6
7
8
The ascending arrangement of \(\dfrac{2}{3},\ \dfrac{6}{7},\ \dfrac{13}{21}\) is:
\(\dfrac{6}{7},\ \dfrac{2}{3},\ \dfrac{13}{21}\)
\(\dfrac{13}{21},\ \dfrac{2}{3},\ \dfrac{6}{7}\)
\(\dfrac{6}{7},\ \dfrac{13}{21},\ \dfrac{2}{3}\)
\(\dfrac{2}{3},\ \dfrac{6}{7},\ \dfrac{13}{21}\)
Reciprocal of the fraction \(\dfrac{2}{3}\) is:
2
3
\(\dfrac{2}{3}\)
\(\dfrac{3}{2}\)
The product of \(\dfrac{11}{13}\) and \(4\) is:
\(3\dfrac{5}{13}\)
\(5\dfrac{3}{13}\)
\(13\dfrac{3}{5}\)
\(13\dfrac{5}{3}\)
The product of \(3\) and \(4\dfrac{2}{5}\) is:
\(17\dfrac{2}{5}\)
\(\dfrac{24}{5}\)
\(13\dfrac{1}{5}\)
\(5\dfrac{1}{13}\)
Pictorial representation of \(3 \times \dfrac{2}{3}\) is:
(a)
(b)
(c)
(d)
\(\dfrac{1}{5} \div \dfrac{4}{5}\) equal to:
\(\dfrac{4}{5}\)
\(\dfrac{1}{5}\)
\(\dfrac{5}{4}\)
\(\dfrac{1}{4}\)
The product of \(0.03 \times 0.9\) is:
2.7
0.27
0.027
0.0027
\(\dfrac{5}{7} \div 6\) is equal to:
\(\dfrac{30}{7}\)
\(\dfrac{5}{42}\)
\(\dfrac{30}{42}\)
\(\dfrac{6}{7}\)
\(5\dfrac{1}{6} \div \dfrac{9}{2}\) is equal to
\(\dfrac{31}{6}\)
\(\dfrac{1}{27}\)
\(5\dfrac{1}{27}\)
\(\dfrac{31}{27}\)
Which of the following represents \(\dfrac{1}{3}\) of \(\dfrac{1}{6}\)?
\(\dfrac{1}{3}+\dfrac{1}{6}\)
\(\dfrac{1}{3}-\dfrac{1}{6}\)
\(\dfrac{1}{3}\times\dfrac{1}{6}\)
\(\dfrac{1}{3}\div\dfrac{1}{6}\)
\(\dfrac{3}{7}\) of \(\dfrac{2}{5}\) is equal to
\(\dfrac{5}{12}\)
\(\dfrac{5}{35}\)
\(\dfrac{1}{35}\)
\(\dfrac{6}{35}\)
One packet of biscuits requires \(2\dfrac{1}{2}\) cups of flour and \(1\dfrac{2}{3}\) cups of sugar. Estimated total quantity of both ingredients used in 10 such packets will be
less than 30 cups
between 30 cups and 40 cups
between 40 cups and 50 cups
above 50 cups
The product of \(7\) and \(6\dfrac{3}{4}\) is
\(42\dfrac{1}{4}\)
\(47\dfrac{1}{4}\)
\(42\dfrac{3}{4}\)
\(47\dfrac{3}{4}\)
On dividing \(7\) by \(\dfrac{2}{5}\), the result is
\(\dfrac{14}{2}\)
\(\dfrac{35}{4}\)
\(\dfrac{14}{5}\)
\(\dfrac{35}{2}\)
\(2\dfrac{2}{3} \div 5\) is equal to
\(\dfrac{8}{15}\)
\(\dfrac{40}{3}\)
\(\dfrac{40}{5}\)
\(\dfrac{8}{3}\)
\(\dfrac{4}{5}\) of 5 kg apples were used on Monday. The next day \(\dfrac{1}{3}\) of what was left was used. Weight (in kg) of apples left now is
\(\dfrac{2}{7}\)
\(\dfrac{1}{14}\)
\(\dfrac{2}{3}\)
\(\dfrac{4}{21}\)
The picture interprets

\(\dfrac{1}{4}\div 3\)
\(3\times\dfrac{1}{4}\)
\(\dfrac{3}{4}\times 3\)
\(3\div \dfrac{1}{4}\)