On dividing \(7\) by \(\dfrac{2}{5}\), the result is
\(\dfrac{14}{2}\)
\(\dfrac{35}{4}\)
\(\dfrac{14}{5}\)
\(\dfrac{35}{2}\)
\(7\div\dfrac{2}{5}=7\times\dfrac{5}{2}=\dfrac{35}{2}\).