The product of \(7\) and \(6\dfrac{3}{4}\) is
\(42\dfrac{1}{4}\)
\(47\dfrac{1}{4}\)
\(42\dfrac{3}{4}\)
\(47\dfrac{3}{4}\)
\(6\dfrac{3}{4}=\dfrac{27}{4}\). So \(7\times\dfrac{27}{4}=\dfrac{189}{4}=47\dfrac{1}{4}\).