NCERT Exemplar Solutions
Class 7 - Mathematics - Unit 2: Fractions and Decimals - Multiple Choice QuestionsQuestion 16
Class 7 - Mathematics - Unit 2: Fractions and Decimals - Multiple Choice Questions
Question. 16
The product of \(7\) and \(6\dfrac{3}{4}\) is
(a)
\(42\dfrac{1}{4}\)
(b)
\(47\dfrac{1}{4}\)
(c)
\(42\dfrac{3}{4}\)
(d)
\(47\dfrac{3}{4}\)
Detailed Answer with Explanation:
\(6\dfrac{3}{4}=\dfrac{27}{4}\). So \(7\times\dfrac{27}{4}=\dfrac{189}{4}=47\dfrac{1}{4}\).