In Fig. 5.29, PQ ∥ RS and a : b = 3 : 2. Then f is equal to
(a) 36°
(b) 108°
(c) 72°
(d) 144°
a:b=3:2. So let a=3k, b=2k. Then a+b=180 ⇒ 5k=180 ⇒ k=36. So a=108, b=72. f corresponds to a =108°.